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Order an array of words based on another array of words JavaScript
Let’s say, we have the following array of objects sorted according to its id property −
const unordered = [{
id: 1,
string: 'sometimes'
}, {
id: 2,
string: 'be'
}, {
id: 3,
string: 'can'
}, {
id: 4,
string: 'life'
}, {
id: 5,
string: 'tough'
}, {
id: 6,
string: 'very'
}, ];And another array of string like this −
const ordered = ['Life', 'sometimes', 'can', 'be', 'very', 'tough'];
We have to sort the first array so its string property have the same order of string as it is in the second array. Therefore, let’s write the code for this.
Example
const unordered = [{
id: 1,
string: 'sometimes'
}, {
id: 2,
string: 'be'
}, {
id: 3,
string: 'can'
}, {
id: 4,
string: 'life'
}, {
id: 5,
string: 'tough'
}, {
id: 6,
string: 'very'
}, ];
const ordered = ['Life', 'sometimes', 'can', 'be', 'very', 'tough'];
const sorter = (a, b) => {
return ordered.indexOf(a.string) - ordered.indexOf(b.string);
};
unordered.sort(sorter);
console.log(unordered);Output
The output in the console will be −
[
{ id: 4, string: 'life' },
{ id: 1, string: 'sometimes' },
{ id: 3, string: 'can' },
{ id: 2, string: 'be' },
{ id: 6, string: 'very' },
{ id: 5, string: 'tough' }
]
Updated on: 21-Aug-2020
255 Views
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