Order an array of words based on another array of words JavaScript

Javascript Web Development Object Oriented Programming

Let’s say, we have the following array of objects sorted according to its id property −

const unordered = [{
   id: 1,
   string: 'sometimes'
}, {
   id: 2,
   string: 'be'
}, {
   id: 3,
   string: 'can'
}, {
   id: 4,
   string: 'life'
}, {
   id: 5,
   string: 'tough'
}, {
   id: 6,
   string: 'very'
}, ];

And another array of string like this −

const ordered = ['Life', 'sometimes', 'can', 'be', 'very', 'tough'];

We have to sort the first array so its string property have the same order of string as it is in the second array. Therefore, let’s write the code for this.

Example

const unordered = [{
   id: 1,
   string: 'sometimes'
}, {
   id: 2,
   string: 'be'
}, {
   id: 3,
   string: 'can'
}, {
   id: 4,
   string: 'life'
}, {
   id: 5,
   string: 'tough'
}, {
   id: 6,
   string: 'very'
}, ];
const ordered = ['Life', 'sometimes', 'can', 'be', 'very', 'tough'];
const sorter = (a, b) => {
   return ordered.indexOf(a.string) - ordered.indexOf(b.string);
};
unordered.sort(sorter);
console.log(unordered);

Output

The output in the console will be −

[
   { id: 4, string: 'life' },
   { id: 1, string: 'sometimes' },
   { id: 3, string: 'can' },
   { id: 2, string: 'be' },
   { id: 6, string: 'very' },
   { id: 5, string: 'tough' }
]

AmitDiwan

Published on 21-Aug-2020 14:06:04

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