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Filter an object based on an array JavaScript
Let’s say. we have an array and an object like this −
const arr = ['a', 'd', 'f'];
const obj = {
"a": 5,
"b": 8,
"c": 4,
"d": 1,
"e": 9,
"f": 2,
"g": 7
};
We are required to write a function that takes in the object and the array and filter away all the object properties that are not an element of the array. So, the output should only contain 3 properties, namely: “a”, “d” and “e”.
Let’s write the code for this function −
Example
const arr = ['a', 'd', 'f'];
const obj = {
"a": 5,
"b": 8,
"c": 4,
"d": 1,
"e": 9,
"f": 2,
"g": 7
};
const filterObject = (obj, arr) => {
Object.keys(obj).forEach((key) => {
if(!arr.includes(key)){
delete obj[key];
};
});
};
filterObject(obj, arr);
console.log(obj);
Output
The output in the console will be −
{ a: 5, d: 1, f: 2 }Advertisements