# Number of pairs with Bitwise OR as Odd number in C++

C++Server Side ProgrammingProgramming

In this tutorial, we are going to write a program that counts the number of pairs in the given array whose bitwise OR is an odd number.

Let's see the steps to solve the problem.

• Write two loops to get the pairs of the array.

• Compute the bitwise OR between every pair.

• Increment the count if the result is an odd number.

## Example

Let's see the code.

Live Demo

#include <bits/stdc++.h>
using namespace std;
int getOddPairsCount(int arr[], int n) {
int count = 0;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
if ((arr[i] | arr[j]) % 2 != 0) {
count++;
}
}
}
return count;
}
int main() {
int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int n = 10;
cout << getOddPairsCount(arr, n) << endl;
return 0;
}

## Output

If you run the above code, then you will get the following result.

35

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

Published on 03-Jul-2021 08:31:52