Multiply a Legendre series by an independent variable in Python

To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy. The method returns an array representing the result of the multiplication. Returns the difference of two Legendre series c1 - c2. The arguments are sequences of coefficients ordered from lowest order term to highest, i.e., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2. The parameter, c is a 1-D array of Legendre series coefficients ordered from low to high.

Steps

At first, import the required library −

import numpy as np
from numpy.polynomial import laguerre as L

Create an array −

c = np.array([1, 2, 3])

Display the array −

print("Our Array...\n",c)

Check the Dimensions −

print("\nDimensions of our Array...\n",c.ndim)

Get the Datatype −

print("\nDatatype of our Array object...\n",c.dtype)

Get the Shape −

print("\nShape of our Array object...\n",c.shape)

To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy −

print("\nResult....\n",L.legmulx(c))

Example

import numpy as np
from numpy.polynomial import legendre as L

# Create an array
c = np.array([1, 2, 3])

# Display the array
print("Our Array...\n",c)

# Check the Dimensions
print("\nDimensions of our Array...\n",c.ndim)

# Get the Datatype
print("\nDatatype of our Array object...\n",c.dtype)

# Get the Shape
print("\nShape of our Array object...\n",c.shape)

# To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy
print("\nResult....\n",L.legmulx(c))

Output

Our Array...
   [1 2 3]

Dimensions of our Array...
1

Datatype of our Array object...
int64

Shape of our Array object...
(3,)

Result....
   [0.66666667 2.2 1.33333333 1.8 ]

AmitDiwan

e

Updated on: 07-Mar-2022

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