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Michael finished colouring a picture in $\frac{7}{12}$ hour. Vaibhav finished colouring the same picture in $\frac{3}{4}$ hour. Who worked longer? By what fraction was it longer?
Given:
Michael finished coloring a picture in $\frac{7}{12}$ hour.
To do:
We have to find who worked longer and by what fraction it was longer.
Solution:
Time taken by Michael to colour the picture $=\frac{7}{12}$ hour
Time taken by Vaibhav to colour the picture $=\frac{3}{4}$ hour
Comparing fractions $\frac{7}{12}$ and $\frac{3}{4}$, we get,
LCM of 12 and 4 is 12
This implies,
$\frac{3}{4}=\frac{3\times3}{4\times3}$
$=\frac{9}{12}$
Here, $\frac{9}{12}>\frac{7}{12}$
This implies,
Vaibhav worked for longer time.
Vaibhav worked for longer time by,
$\frac{9}{12}-\frac{7}{12}=\frac{9-7}{12}$
$=\frac{2}{12}$
$=\frac{1}{6}$
Therefore,
Vaibhav worked longer by a fraction of $\frac{1}{6}$ hour.
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