Solve the following

$(\frac{-3}{7})^{2} $ $\div$ $(\frac{7}{3})^{\frac{12}{-4}}$

Given: 

$(\frac{-3}{7})^{2} $ $\div$   $(\frac{7}{3})^{\frac{12}{-4}}$

To do:  Solve the given expression.

Solution:

$(\frac{-3}{7})^{2} $ $\div$   $(\frac{7}{3})^{\frac{12}{-4}}$

= $(\frac{-3}{7})^{2}$  $\div$   $(\frac{7}{3})^{-3}$

= $(\frac{-3}{7})^{2}$  $\times$   $(\frac{3}{7})^{-3}$

= $(\frac{-3}{7})^{2}$   $\times$   $(\frac{7}{3})^{3}$

= $\frac{9}{49}$ $\times$ $\frac{49 \times7}{9 \times3}$

=  $\frac{7}{3}$

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Updated on: 10-Oct-2022

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