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# Largest number less than X having at most K set bits in C++

In this tutorial, we are going to write a program that finds the largest number which is less than given x and should have at most k set bits.

Let's see the steps to solve the problem.

- Initialise the numbers x and k.
- Find the set bits in the number x.
- Write a loop that iterates set bits count of x - k.
- Update the value of x with x & (x - 1).

- Return x.

## Example

Let's see the code.

#include <bits/stdc++.h> using namespace std; int largestNumberWithKBits(int x, int k) { int set_bit_count = __builtin_popcount(x); if (set_bit_count <= k) { return x; } int diff = set_bit_count - k; for (int i = 0; i < diff; i++) { x &= (x - 1); } return x; } int main() { int x = 65, k = 2; cout << largestNumberWithKBits(x, k) << endl; return 0; }

## Output

If you run the above code, then you will get the following result.

65

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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