Suppose we have an unsorted array, we have to find the kth largest element from that array. So if the array is [3,2,1,5,6,4] and k = 2, then the result will be 5.
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
class Solution(object): def findKthLargest(self, nums, k): nums.sort() if k ==1: return nums[-1] temp = 1 return nums[len(nums)-k] ob1 = Solution() print(ob1.findKthLargest([56,14,7,98,32,12,11,50,45,78,7,5,69], 5))