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Kth odd number in an array in C++
In this tutorial, we are going to write a program that finds the k-th odd number from the given array.
Let's see the steps to solve the problem.
- Initialise the array and k.
- Iterate over the array.
- If the current element is odd, then decrement the value of k.
- If k is 0, then return the current element.
- Return -1.
Example
Let's see the code.
#include <bits/stdc++.h>
using namespace std;
int findKthOddNumber(int arr[], int n, int k) {
for (int i = 0; i <= n; i++) {
if (arr[i] % 2 == 1) {
k--;
}
if (k == 0) {
return arr[i];
}
}
return -1;
}
int main() {
int arr[] = { 4, 5, 22, 1, 55 }, k = 3;
cout << findKthOddNumber(arr, 5, k) << endl;
return 0;
}Output
If you run the above code, then you will get the following result.
55
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Updated on: 09-Apr-2021
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