# Java Program to Check whether the input number is a Neon Number

JavaObject Oriented ProgrammingProgramming

In this article, we will understand how to check whether the input number is a neon number. A neon number is such a number whose sum of digits of square of the number is equal to the number.

Below is a demonstration of the same −

Input

Suppose our input is −

9

Output

The desired output would be the following because 92 = 81 i.e. 8 + 1 = 9

The given input is a neon number


## Algorithm

Step1- Start
Step 2- Declare an integers my_input
Step 3- Prompt the user to enter an integer value/ Hardcode the integer
Step 5- Compute the square of the input and store it in a variable input_square
Step 6- Compute the sum of the of the digits of input_square and compare the result with my_input
Step 6- If the input matches, then the input number is a neon number
Step 7- If not, the input is not a neon number.
Step 8- Display the result
Step 9- Stop

## Example 1

Here, the input is being entered by the user based on a prompt. You can try this example live in ourcoding ground tool .

import java.util.Scanner;
public class NeonNumbers{
public static void main(String[] args){
int my_input, input_square, sum=0;
Scanner my_scanner = new Scanner(System.in);
System.out.println("Required packages have been imported");
System.out.println("A scanner object has been defined ");
System.out.println("Enter the number: ");
my_input=my_scanner.nextInt();
input_square=my_input*my_input;
while(input_square>0){
sum=sum+input_square%10;
input_square=input_square/10;
}
if(sum!=my_input)
System.out.println("The given input is not a Neon number.");
else
System.out.println("The given input is Neon number.");
}
}

## Output

Required packages have been imported
A scanner object has been defined
Enter the number:
9
The given input is Neon number.

## Example 2

Here, the integer has been previously defined, and its value is accessed and displayed on the console.

public class NeonNumbers{
public static void main(String[] args){
int my_input, input_square, sum=0;
my_input= 9;
System.out.printf("The number is %d ", my_input);
input_square=my_input*my_input;
while(input_square<0){
sum=sum+input_square%10;
input_square=input_square/10;
}
if(sum!=my_input)
System.out.println("\nThe given input is not a Neon number.");
else
System.out.println("\nThe given input is Neon number.");
}
}

## Output

The number is 9
The given input is Neon number.