Program to check whether a number is Proth number or not in C++

Given with a number ‘n’ and the task is to determine whether the given positive integer is a proth or not and display the result as an output.

What is Proth Number?

A proth number is given by

$$N=k\cdot\:2^{n}+1$$

Where, n is a positive integer and k is a odd positive integer

The first few proth numbers are given below −

3, 5, 9, 13, 17, 25, 33, 41, 49, 57, 65, 81, 97.......

Input

number: 17

Output

its a proth number

Input

number: 18

Output

its not a proth number

Approach used in the given program is as follows

Input the number to check for the condition
Apply the given formula to check whether its a proth number or not
If the condition holds true print its a proth number
If the condition doesn’t holds true print its not a proth number

Algorithm

Step 1→ declare function to calculate power of 2
   bool isPower(int num)
      return (num && !(num & (num - 1)))
Step 2→ Declare function to check if a number is a proth number or not
   bool isProth(int num)
      declare int k = 1
      While (k < (num / k))
         IF (num % k == 0)
            IF (isPower(num / k))
               return true
            End
            Set k = k + 2
         End
      End
      return false
Step 3→ In main()
   Declare int num = 17
   IF (isProth(num - 1))
      Print "its a proth number"
   End
   Else
      Print "its not a proth number"
End

Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
//function to calculate power of 2
bool isPower(int num){
   return (num && !(num & (num - 1)));
}
//function to check if a number is a proth number
bool isProth(int num){
   int k = 1;
   while (k < (num / k)){
      if (num % k == 0){
         if (isPower(num / k))
            return true;
      }
      k = k + 2;
   }
   return false;
}
int main(){
   int num = 17;
   if (isProth(num - 1))
      cout << "its a proth number";
   else
      cout << "its not a proth number";
   return 0;
}