Java Program to check whether the character is ASCII 7 bit numeric

Java 8 Object Oriented Programming Programming

To check whether the entered value is ASCII 7-bit numeric, check the character from ‘0’ to ‘9’.

Here, we have a numeric character.

char one = '9';

Now, we have checked a condition with if-else for numeric character from ‘0’ to ‘9’

if (c >= '0' && c <= '9') {
   System.out.println("Given value is numeric!");
} else {
   System.out.println("Given value is not numeric!");
}

Example

Live Demo

public class Demo {
   public static void main(String []args) {
      char c = '9';
      System.out.println("Given value = "+c);
      if (c >= '0' && c <= '9') {
         System.out.println("Given value is numeric!");
      } else {
         System.out.println("Given value is not numeric!");
      }
   }
}

Output

Given value = 9
Given value is numeric!

Let us see another example wherein we check for numeric character. But, here the given value to be checked is not numeric.

Example

Public class Demo {
   public static void main(String []args) {
      char c = 's';
      System.out.println("Given value = "+c);
      if (c >= '0' && c <= '9') {
         System.out.println("Given value is numeric!");
      } else {
         System.out.println("Given value is not numeric!");
      }
   }
}

Output

Given value = s
Given value is not numeric!

Let us see one more example now wherein we check for numeric character. But, here the given value to be checked is not numeric.

Example

public class Demo {
   public static void main(String []args) {
      char c = '-';
      System.out.println("Given value = "+c);
      if (c >= '0' && c <= '9') {
         System.out.println("Given value is numeric!");
      } else {
         System.out.println("Given value is not numeric!");
      }
   }
}

Output

Given value = -
Given value is not numeric!

karthikeya Boyini

Updated on 25-Jun-2020 13:38:30

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