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Java Program to check whether the entered value is ASCII 7 bit alphabetic
To check whether the entered value is ASCII 7-bit alphabetic, check the character from ‘a’ to ‘z’ or ‘A’ to ‘Z’.
Here, we have a character.
char one = 'r';
Now, we have checked a condition with if-else to check for character from ‘a’ to ‘z’ or ‘A’ to ‘Z’.
if ((one >= 'A' && one <= 'Z') || (one >= 'a' && one <= 'z')) { System.out.println("Given value is an alphabet!"); } else { System.out.println("Given value is not an alphabet!"); }
Example
public class Demo { public static void main(String []args) { char one = 'r'; System.out.println("Character: "+one); if ((one >= 'A' && one <= 'Z') || (one >= 'a' && one <= 'z')) { System.out.println("Given value is an alphabet!"); } else { System.out.println("Given value is not an alphabet!"); } } }
Output
Character: r Given value is an alphabet!
Let us see another example
Example
public class Demo { public static void main(String []args) { char one = '1'; System.out.println("Character: "+one); if ((one >= 'A' && one <= 'Z') || (one >= 'a' && one <= 'z')) { System.out.println("Given value is an alphabet!"); } else { System.out.println("Given value is not an alphabet!"); } } }
Output
Character: 1 Given value is not an alphabet!
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