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C++ Program to Check Whether a character is Vowel or Consonant
Vowels are the alphabets a, e, i, o, u. All the rest of the alphabets are known as consonants.
The program to check if a character is a vowel or consonant is as follows −
Example
#include <iostream>
using namespace std;
int main() {
char c = 'a';
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' )
cout <<c<< " is a Vowel" << endl;
else
cout <<c<< " is a Consonant" << endl;
return 0;
}Output
a is a Vowel
In the above program, an if statement is used to find if the character is a, e, i, o or u. If it is any of these, it is a vowel. Otherwise, it is a consonant.
This is shown in the below code snippet.
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ) cout <<c<< " is a Vowel" << endl; else cout <<c<< " is a Consonant" << endl;
The above program checks only for lower case characters. So, a program that checks for upper case as well as lower case characters is as follows −
Example
#include <iostream>
using namespace std;
int main() {
char c = 'B';
if (c == 'a' || c == 'e' || c == 'i' ||
c == 'o' || c == 'u' || c == 'A' ||
c == 'E' || c == 'I' || c == 'O' || c == 'U')
cout <<c<< " is a Vowel" << endl;
else
cout <<c<< " is a Consonant" << endl;
return 0;
}B is a Consonant
In the above program, an if statement is used to find if the character is a, e, i, o or u (both in upper case as well as lower case).. If it is any of these, it is a vowel. Otherwise, it is a consonant.
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' || c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') cout <<c<< " is a Vowel" << endl; else cout <<c<< " is a Consonant" << endl;
Updated on: 24-Jun-2020
9K+ Views
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