How to match a white space equivalent using Java RegEx?

The metacharacter "\s" matches the white space characters in the given string.

Example 1

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
   public static void main(String args[]) {
      //Reading String from user
      System.out.println("Enter a String");
      Scanner sc = new Scanner(;
      String input = sc.nextLine();
      String regex = "\s";
      //Compiling the regular expression
      Pattern pattern = Pattern.compile(regex);
      //Retrieving the matcher object
      Matcher matcher = pattern.matcher(input);
      int count = 0;
      while(matcher.find()) {
      System.out.println("Number of spaces: "+count);


Enter a String
Hello how are you welcome to tutorialspoint
Number of spaces: 6

Example 2

import java.util.Scanner;
public class RegexExample {
   public static void main( String args[] ) {
      //regular expression
      String regex = "\s+";
      System.out.println("Enter input value: ");
      Scanner sc = new Scanner(;
      String input = sc.nextLine();
      String result = input.replaceAll(regex, "");
      System.out.println("Result: "+result);


Enter input value:
hello how are you
Result: hellohowareyou

Updated on: 19-Nov-2019

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