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How to match non-word boundaries using Java RegEx?
You can match the non-word boundaries using the meta character “\B”.
Example 1
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String args[]) {
//Reading String from user
System.out.println("Enter a String");
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
String regex = "\B";
//Compiling the regular expression
Pattern pattern = Pattern.compile(regex);
//Retrieving the matcher object
Matcher matcher = pattern.matcher(input);
int count = 0;
while(matcher.find()) {
count++;
}
System.out.println("Number of non-word boundaries: "+count);
}
}Output
Enter a String this is a sample text Number of non-word boundaries: 12
Example 2
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main( String args[] ) {
String regex = "\Bin";
Scanner sc = new Scanner(System.in);
System.out.println("Enter a string: ");
String input = sc.nextLine();
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(input);
int count = 0;
while(m.find()) {
count++;
}
System.out.println("no of non-word boundaries: "+count);
}
}Output
Enter a string: this is a sample text in win tin pin sin no of non-word boundaries: 4
Updated on: 19-Nov-2019
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