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How to match word boundaries using Java RegEx?
You can match the word boundaries using the meta character “\b”.
Example 1
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String args[]) {
//Reading String from user
System.out.println("Enter a String");
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
String regex = "\b";
//Compiling the regular expression
Pattern pattern = Pattern.compile(regex);
//Retrieving the matcher object
Matcher matcher = pattern.matcher(input);
int count = 0;
while(matcher.find()) {
count++;
}
System.out.println("Number of word boundaries: "+count);
}
}Output
Enter a String this is a sample text Number of word boundaries: 10
Example 2
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class FirstLetterExample {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter sample text: ");
String data = sc.nextLine();
String regex = "\b[a-zA-Z]";
//Creating a pattern object
Pattern pattern = Pattern.compile(regex);
//Creating a Matcher object
Matcher matcher = pattern.matcher(data);
System.out.println("First letter of each word from the given string: ");
while(matcher.find()) {
System.out.print(matcher.group()+" ");
}
}
}Output
Enter sample text: National Intelligence Agency Research & Analysis Wing First letter of each word from the given string: N I A R A W
Updated on: 19-Nov-2019
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