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How to divide the data frame rows in R by row standard deviation?
To divide the data frame row values by row standard deviation in R, we can follow the below steps −
- First of all, create a data frame.
- Then, use apply function to divide the data frame row values by row standard deviation.
Creating the data frame
Let's create a data frame as shown below −
> x<-round(rnorm(25),2) > y<-round(rnorm(25),2) > df<-data.frame(x,y) > df
On executing, the above script generates the below output(this output will vary on your system due to randomization) −
x y 1 1.48 0.86 2 -0.14 -0.58 3 -0.25 1.22 4 0.18 0.25 5 0.50 0.68 6 -1.34 -0.21 7 0.43 -0.54 8 0.32 -1.00 9 0.09 -0.19 10 1.20 -1.23 11 -1.48 0.73 12 -0.67 -0.19 13 -1.54 0.09 14 0.51 0.16 15 -1.38 0.05 16 -0.33 1.69 17 0.96 0.95 18 -0.70 -1.56 19 -0.53 0.42 20 0.01 0.77 21 -0.99 -1.76 22 -0.06 -0.34 23 -0.91 0.80 24 -1.01 -1.36 25 1.45 -0.35
Dividing the data frame row values by row standard deviation
Using apply function to divide the row values of df by row standard deviation −
Using col Means function to find the column means −
> x<-round(rnorm(25),2) > y<-round(rnorm(25),2) > df<-data.frame(x,y) > df_new<-t(apply(df,1, function(x) x/sd(x))) > df_new
Output
x y [1,] 3.37586463 1.96165107 [2,] -0.44997704 -1.86419060 [3,] -0.24051251 1.17370105 [4,] 3.63654916 5.05076272 [5,] 3.92837101 5.34258457 [6,] -1.67703201 -0.26281845 [7,] 0.62691941 -0.78729415 [8,] 0.34283965 -1.07137391 [9,] 0.45456865 -0.95964492 [10,] 0.69837707 -0.71583649 [11,] -0.94707515 0.46713842 [12,] -1.97400643 -0.55979287 [13,] -1.33612815 0.07808541 [14,] 2.06071119 0.64649763 [15,] -1.36476554 0.04944803 [16,] -0.23103489 1.18317867 [17,] 135.76450199 134.35028843 [18,] -1.15110406 -2.56531762 [19,] -0.78898230 0.62523126 [20,] 0.01860807 1.43282164 [21,] -1.81827458 -3.23248814 [22,] -0.30304576 -1.71725933 [23,] -0.75259318 0.66162038 [24,] -4.08101628 -5.49522984 [25,] 1.13922759 -0.27498597
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