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Golang Program to turn on the k’th bit in a number.
Example
For example consider n = 20(00010100), k = 4. So result after turning on 4th bit => 00010000 | (1 << (4-1))
Approach to solve this problem
Step 1 − Define a method, where n and k would be the arguments, returns type is int.
Step 2 − Perform AND operation with n | (1<<(k-1)).
Step 3 − Return the obtained number.
Example
package main
import (
"fmt"
"strconv"
)
func TurnOnKthBit(n, k int) int {
return n | (1 << (k-1))
}
func main(){
var n = 20
var k = 4
fmt.Printf("Binary of %d is: %s.\n", n, strconv.FormatInt(int64(n), 2))
newNumber := TurnOnKthBit(n, k)
fmt.Printf("After turning on %d th bit of %d is: %d.\n", k, n, newNumber)
fmt.Printf("Binary of %d is: %s.\n", newNumber,
strconv.FormatInt(int64(newNumber), 2))
}Output
Binary of 20 is: 10100. After turning on 4 th bit of 20 is: 28. Binary of 28 is: 11100.
Updated on: 17-Mar-2021
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