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First X vowels from a string in C++
In this problem, we are given string str[] of size N and an integer X. Our task is to create a program to print First X vowels from a string.
We will print first X vowels from the string and if less than X vowels are present, print -1.
Let's take an example to understand the problem,
Input: str = "learn C programming language", X = 5 Output: e, a, o, a, i Vowels are a, e, i, o, u
Solution Approach
A simple solution to the problem is by traversing the string character by charter. And storing all the vowels of the string to a vowels string. And if the length of this string is equal to X, return it. If all vowels of the string cannot make the count upto X, return -1.
Example
Program to illustrate the working of our solution
#include <iostream>
#include <string.h>
using namespace std;
bool isaVowel(char c){
c = tolower(c);
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')
return true;
return false;
}
string findXVowelsString(string s, int x){
string vowelsString = "";
for (int i = 0; i < s.length(); i++) {
if (isaVowel(s[i]))
vowelsString += s[i];
if (vowelsString.length() == x) {
return vowelsString;
}
}
return "-1";
}
int main(){
string str = "learn C programming language";
int x = 5;
cout<<"The first "<<x<<" vowels from the string are "<<findXVowelsString(str, x);
return 0;
}Output
The first 5 vowels from the string are eaoai
Updated on: 01-Feb-2022
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