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To count Vowels in a string using Pointer in C++ Program
Finding the number of vowels in a string using pointers need you to understand string, vowels and how to use pointer with string.
String is an array of characters. And vowels are characters from the set {a,e,i,o,u}. Pointer is a variable that stores the value of memory location on a variable.
To find the number of vowels in a string. We will traverse the string and then compare each character with vowels and if it is equal then it increase a counter otherwise not.
Condition of the below code is that it requires a string that has all lowercase characters. If not you can use tolower() method.
Example
#include <iostream>
using namespace std;
int main() {
char str[] = "i love tutorials point";
char *prt ;
prt = str;
int count = 0;
for(prt;(*prt) != '\0'; prt++) {
if (*prt == 'a' || *prt == 'e' || *prt == 'i'|| *prt == 'o' || *prt == 'u') {
count++;
}
}
cout << "Vowels in the string: " << count;
return 0;
}Output
Vowels in the string: 9
Updated on: 08-Aug-2019
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