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C++ Program to count Vowels in a string using Pointer?
To get the vowels from a string, we have to iterate through each character of the string. Here we have to use pointers to move through the string. For this we need C style strings. If the string is pointed by str, then *str will hold the first character at the beginning. Then if str is increased, the *str will point next character and so on. If the character is in [a,e,i,o,u] or [A, E, I, O, U] then it is vowel. So we will increase the count
Algorithm
countVowels(str)
begin count := 0 for each character ch in str, do if ch is in [a,e,i,o,u] or [A, E, I, O, U], then count := count + 1 end if done return count end
Example
#include<iostream>
using namespace std;
int countVowels(const char *myStr){
int count = 0;
while((*myStr) != '\0'){
if(*myStr == 'a' || *myStr == 'e' || *myStr == 'i' || *myStr == 'o' || *myStr == 'u' || *myStr == 'A' || *myStr == 'E' || *myStr == 'I' || *myStr == 'O' || *myStr == 'U') {
count++;
}
myStr++;
}
return count;
}
main() {
string myStr;
cout << "Enter String: ";
cin >> myStr;
cout << "Number of Vowels: " << countVowels(myStr.c_str());
}Output
Enter String: EDucation Number of Vowels: 5
Updated on: 30-Jul-2019
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