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Finding nth element of an increasing sequence using JavaScript
Problem
Consider an increasing sequence which is defined as follows −
- The number seq(0) = 1 is the first one in seq.
- For each x in seq, then y = 2 * x + 1 and z = 3 * x + 1 must be in seq too.
- There are no other numbers in seq.
Therefore, the first few terms of this sequence will be −
[1, 3, 4, 7, 9, 10, 13, 15, 19, 21, 22, 27, ...]
We are required to write a function that takes in a number n and returns the nth term of this sequence.
Example
Following is the code −
const num = 10;
const findNth = n => {
let seq = [1], x = 0, y = 0
for (let i = 0; i < n; i++) {
let nextX = 2 * seq[x] + 1, nextY = 3 * seq[y] + 1
if (nextX <= nextY) {
seq.push(nextX)
x++
if (nextX == nextY)
y++
} else {
seq.push(nextY)
y++
}
}
return seq[n];
}
console.log(findNth(num));Output
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Updated on: 17-Apr-2021
137 Views
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