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Finding Armstrong numbers in a given range in JavaScript
A number is called Armstrong number if the following equation holds true for that number: xy...z =xx +yy+...+zz, where n denotes the number of digits in the number.
For example:
153 is an Armstrong number because −
11 +55 +33 = 1 + 125 + 27 =153
We are required to write a JavaScript function that takes in two numbers, a range, and returns all the numbers between them that are Armstrong numbers (including them, if they are Armstrong)
Example
The code for this will be −
const isArmstrong = number => {
let num = number;
const len = String(num).split("").length;
let res = 0;
while(num){
const last = num % 10;
res += Math.pow(last, len);
num = Math.floor(num / 10);
};
return res === number;
};
const armstrongBetween = (lower, upper) => {
const res = [];
for(let i = lower; i <= upper; i++){
if(isArmstrong(i)){
res.push(i);
};
};
return res;
};
console.log(armstrongBetween(1, 400));Output
The output in the console −
[ 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371 ]
Updated on: 15-Oct-2020
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