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Armstrong numbers between a range - JavaScript
A number is called Armstrong number if the following equation holds true for that number −
xy..z = x^n + y^n+.....+ z^n
Where, n denotes the number of digits in the number
For example − 370 is an Armstrong number because −
3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370
We are required to write a JavaScript function that takes in two numbers, a range, and returns all the numbers between them that are Armstrong numbers (including them, if they are Armstrong).
Example
Let’s write the code for this function −
const isArmstrong = number => { let num = number; const len = String(num).split("").length; let res = 0; while(num){ const last = num % 10; res += Math.pow(last, len); num = Math.floor(num / 10); }; return res === number; }; const armstrongBetween = (lower, upper) => { const res = []; for(let i = lower; i <= upper; i++){ if(isArmstrong(i)){ res.push(i); }; }; return res; }; console.log(armstrongBetween(1, 400));
Output
The output in the console: −
[ 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371 ]
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