Armstrong numbers between a range - JavaScript

A number is called Armstrong number if the following equation holds true for that number −

xy..z = x^n + y^n+.....+ z^n

Where, n denotes the number of digits in the number

For example − 370 is an Armstrong number because −

3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

We are required to write a JavaScript function that takes in two numbers, a range, and returns all the numbers between them that are Armstrong numbers (including them, if they are Armstrong).

Example

Let’s write the code for this function −

const isArmstrong = number => {
   let num = number;
   const len = String(num).split("").length;
   let res = 0;
   while(num){
      const last = num % 10;
      res += Math.pow(last, len);
      num = Math.floor(num / 10);
   };
   return res === number;
};
const armstrongBetween = (lower, upper) => {
   const res = [];
   for(let i = lower; i <= upper; i++){
      if(isArmstrong(i)){
         res.push(i);
      };
   };
   return res;
};
console.log(armstrongBetween(1, 400));

Output

The output in the console: −

[
   1,   2, 3, 4,   5,
   6,   7, 8, 9, 153,
   370, 371
]

AmitDiwan

Updated on 15-Sep-2020 09:33:17

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