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# Find other two sides of a right angle triangle in C++

In this problem, we are given an integer a denoting one side of a right angle triangle. We need to check whether it is possible to have a right angle triangle with side a. If it is possible, then find the other two sides of a right angle triangle.

**Let’s take an example to understand the problem,**

## Input

a = 5

## Output

Sides : 5, 12, 13

## Explanation

The sides of right angle are found as 5^{2} + 12^{2} = 13^{2}

## Solution Approach

A simple solution to the problem is using pythagoras theorem. We know that the sides of a right angled triangle follow pythagoras theorem, which is

a^{2}+ b^{2}= c^{2}

Where a and b are sides of the triangle and c is the hypotenuse of the triangle.

Using this, we will calculate values of b and c using a.

## Case 1

If a is even, c = (a^{2}+ 4) + 1 b = (a^{2}+ 4) - 1

## Case 2

If a is odd, c = (a2 + 1)/ 2 c = (a2 - 1)/ 2

**Program to illustrate the working of our solution,**

## Example

#include <bits/stdc++.h> #include <cmath> using namespace std; #define PI 3.1415926535 void printOtherSides(int n) { int b,c; if (n & 1) { if (n == 1) cout << -1 << endl; else{ b = (n*n-1)/2; c = (n*n+1)/2; } } else { if (n == 2) cout << -1 << endl; else{ b = n*n/4-1; c = n*n/4+1; } } cout<<"Sides : a = "<<n<<", b = "<<b<<", c = "<<c<<endl; } int main() { int a = 5; printOtherSides(a); return 0; }

## Output

Sides : a = 5, b = 12, c = 13

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