Day of the Year in Python

Suppose, we have a date in the format “YYYY-MM-DD”. We have to return the day number of the year. So if the date is “2019-02-10”, then this is 41st day of the year.

To solve this, we will follow these steps −

• Suppose D is an array of day count like [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
• Convert the date into list of year, month and day
• if the year is leap year then set date D[2] = 29
• Add up the day count up to the month mm – 1. and day count after that.

Example

Let us see the following implementation to get better understanding −

 Live Demo

class Solution(object):
   def dayOfYear(self, date):
      days = [0,31,28,31,30,31,30,31,31,30,31,30,31]
      d = list(map(int,date.split("-")))
      if d[0] % 400 == 0:
         days[2]+=1
      elif d[0]%4 == 0 and d[0]%100!=0:
         days[2]+=1
      for i in range(1,len(days)):
         days[i]+=days[i-1]
      return days[d[1]-1]+d[2]
ob1 = Solution()
print(ob1.dayOfYear("2019-02-10"))

Input

"2019-02-10"

Output

41