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Find minimum cost to buy all books in C++
Suppose we have an array of n elements. These are the ratings of them. Find the minimum cost to buy all books, with the following condition −
- Cost of each book would be at-least 1 dollar
- A book has higher cost than an adjacent (left or right) if rating is more than the adjacent.
So for example, if the rating array is like [1, 3, 4, 3, 7, 1], Then the output is 10, As 1 + 2 + 3 + 1 + 2 + 1 = 10
To solve this, we have to make two arrays called LtoR, and RtoL, and fill them with 1, now follow these steps −
- Traverse left to right, then fill LtoR, and update it by seeing previous rating of the given array. We are not caring about the next rating of given array
- Traverse right to left, then fill RtoL, and update it by seeing previous rating of the given array. We are not caring about the next rating of given array
- For maximum value of ith position in both array LtoR and RtoL, then add it to the result.
Example
#include<iostream>
using namespace std;
int getMinCost(int ratings[], int n) {
int res = 0;
int LtoR[n];
int RtoL[n];
for(int i = 0; i<n; i++){
LtoR[i] = RtoL[i] = 1;
}
for (int i = 1; i < n; i++)
if (ratings[i] > ratings[i - 1])
LtoR[i] = LtoR[i - 1] + 1;
for (int i = n - 2; i >= 0; i--)
if (ratings[i] > ratings[i + 1])
RtoL[i] = RtoL[i + 1] + 1;
for (int i = 0; i < n; i++)
res += max(LtoR[i], RtoL[i]);
return res;
}
int main() {
int ratings[] = { 1, 6, 8, 3, 4, 1, 5, 7 };
int n = sizeof(ratings) / sizeof(ratings[0]);
cout << "Minimum cost is: " << getMinCost(ratings, n);
}Output
Minimum cost is: 15
Updated on: 18-Dec-2019
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