Divide a big number into two parts that differ by k in C++ Program

In this tutorial, we are going to write a program that divides a number into two parts with a difference of k.

Let's see an example.

Input

n = 100
k = 30

Output

65 35

Here, we need to understand a little bit of math before diving into the problem. Let's see it.

We have a + b = n and a - b = k. By adding the two equations, we get

a = (n + k)/2
b = n - a

Example

That's it. We have n and k. And there is nothing more in it. Let's see the code

 Live Demo

#include <bits/stdc++.h>
using namespace std;
void divideTheNumber(int n, int k) {
   double a = (n + k) / 2;
   double b = n - a;
   cout << a << " " << b << endl;
}
int main() {
   int n = 54, k = 12;
   divideTheNumber(n, k);
}

Output

If you run the above code, then you will get the following result.

33 21

Conclusion

If you have any queries in the tutorial, mention them in the comment section.