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Java Program to divide a number into smaller random ints
We have considered a number 10 here, which will divided into 8 random ints with Random class. The number we have set as HashSet collection −
HashSet<Integer>set = new HashSet<Integer>(); set.add(0); set.add(0); set.add(0); set.add(number);
Now use nextInt to get the next random integer −
intarrSize = parts + 1;
while (set.size() < arrSize) {
set.add(1 + randNum.nextInt(number - 1));
}
Integer[] dividers = set.toArray(new Integer[arrSize]);
Arrays.sort(dividers);
int[] res = new int[parts];
for(int i = 1, j = 0; i < dividers.length; ++i, ++j) {
res[j] = dividers[i] - dividers[j];
}Example
import java.util.Arrays;
import java.util.HashSet;
import java.util.Random;
public class Demo {
public static Random randNum = new Random();
public static int[] DemoFunc(int number, int parts) {
HashSet<Integer>set = new HashSet<Integer>();
set.add(0);
set.add(0);
set.add(0);
set.add(number);
int arrSize = parts + 1;
while (set.size() < arrSize) {
set.add(1 + randNum.nextInt(number - 1));
}
Integer[] dividers = set.toArray(new Integer[arrSize]);
Arrays.sort(dividers);
int[] res = new int[parts];
for(int i = 1, j = 0; i < dividers.length; ++i, ++j) {
res[j] = dividers[i] - dividers[j];
}
return res;
}
public static void main(String[] args) {
System.out.println(Arrays.toString(DemoFunc(10, 8)));
}
}Output
[1, 1, 2, 2, 1, 1, 1, 1]
Updated on: 30-Jul-2019
316 Views
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