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Examine whether $(7)^n$ can end with the digit 5 for any $n\in N$.
Given :
The given number term is $7^n$.
To do :
We have to check whether $(7)^n$ can end with the digit 5 for any $n\in N$.
Solution :
If a number ends with the digit 5, it should have 5 as it's prime factor.
$7^n$
$7 = 1\times 7$
$7^n= (1\times 7)^n$
The number 7 has 1 and 7 as it's prime factors but not 5.
Therefore, it can be concluded that $(7)^n$ cannot end with the digit 5 for any $n\in N$
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