- Trending Categories
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Check whether $6^n$ can end with the digit 0 for any natural number n.
Given: $6^n$.
To do: Here we have to check whether $6^n$ can end with the digit 0 for any natural number $n$.
Solution:
There is no natural number $n$ for which $6^n$ ends with the digit zero.
Explanation:
If $6^n$ is to end with zero for a natural number $n$, it should be divisible by 2 and 5.
This means that the prime factorisation of $6^n$ should contain the prime number 5 and 2.
But it is not possible because;
$6^n\ =\ (2\ \times\ 3)^n\ =\ 2^n\ \times\ 3^n$
Since 5 is not present in the prime factorization, there is no natural number $n$ for which $6^n$ ends with the digit zero.
Advertisements