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C++ Program to Find Transpose of a Matrix
A matrix is a rectangular array of numbers that is arranged in the form of rows and columns. A transpose of a matrix is a new matrix in which the rows of the original are the columns now and vice versa. For example.
A matrix is given below −
1 2 3 4 5 6 7 8 9
The transpose of the above matrix is as follows.
1 4 7 2 5 8 3 6 9
A program to find the transpose of a matrix is as follows −
Example
#include<iostream<
using namespace std;
int main() {
int transpose[10][10], r=3, c=2, i, j;
int a[3][3] = { {1, 2} , {3, 4} , {5, 6} };
cout<<"The matrix is:"<<endl;
for(i=0; i<r; ++i) {
for(j=0; j<c; ++j)
cout<<a[i][j]<<" ";
cout<<endl;
}
cout<<endl;
for(i=0; i<r; ++i)
for(j=0; j<c; ++j) {
transpose[j][i] = a[i][j];
}
cout<<"The transpose of the matrix is:"<<endl;
for(i=0; i<c; ++i) {
for(j=0; j<r; ++j)
cout<<transpose[i][j]<<" ";
cout<<endl;
}
return 0;
}Output
The matrix is: 1 2 3 4 5 6 The transpose of the matrix is: 1 3 5 2 4 6
In the above program, the matrix is initialized. Then its values are displayed. This is shown in the following code snippet.
int a[3][3] = { {1, 2} , {3, 4} , {5, 6} };
cout<<"The matrix is:"<<endl;
for(i=0; i<r; ++i) {
for(j=0; j<c; ++j)
cout<<a[i][j]<<" ";
cout<<endl;
}The transpose of the matrix is calculated using a nested for loop. This is given as follows.
for(i=0; i<r; ++i)
for(j=0; j<c; ++j) {
transpose[j][i] = a[i][j];
}Finally, the transpose is obtained and it is printed on the screen. This is done with the following code snippet.
cout<<"The transpose of the matrix is:"<<endl;
for(i=0; i<c; ++i) {
for(j=0; j<r; ++j)
cout<<transpose[i][j]<<" ";
cout<<endl;
}
Updated on: 24-Jun-2020
11K+ Views
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