C++ Program to Find Transpose of a Matrix

A matrix is a rectangular array of numbers that is arranged in the form of rows and columns. A transpose of a matrix is a new matrix in which the rows of the original are the columns now and vice versa. For example.

A matrix is given below −

1 2 3
4 5 6
7 8 9

The transpose of the above matrix is as follows.

1 4 7
2 5 8
3 6 9

A program to find the transpose of a matrix is as follows −

Example

 Live Demo

#include<iostream<
using namespace std;
int main() {
   int transpose[10][10], r=3, c=2, i, j;
   int a[3][3] = { {1, 2} , {3, 4} , {5, 6} };
   cout<<"The matrix is:"<<endl;
   for(i=0; i<r; ++i) {
      for(j=0; j<c; ++j)
      cout<<a[i][j]<<" ";
      cout<<endl;
   }
   cout<<endl;
   for(i=0; i<r; ++i)
   for(j=0; j<c; ++j) {
      transpose[j][i] = a[i][j];
   }
   cout<<"The transpose of the matrix is:"<<endl;
   for(i=0; i<c; ++i) {
      for(j=0; j<r; ++j)
      cout<<transpose[i][j]<<" ";
      cout<<endl;
   }
   return 0;
}

Output

The matrix is:
1 2
3 4
5 6

The transpose of the matrix is:
1 3 5
2 4 6

In the above program, the matrix is initialized. Then its values are displayed. This is shown in the following code snippet.

int a[3][3] = { {1, 2} , {3, 4} , {5, 6} };
cout<<"The matrix is:"<<endl;
for(i=0; i<r; ++i) {
   for(j=0; j<c; ++j)
   cout<<a[i][j]<<" ";
   cout<<endl;
}

The transpose of the matrix is calculated using a nested for loop. This is given as follows.

for(i=0; i<r; ++i)
for(j=0; j<c; ++j) {
   transpose[j][i] = a[i][j];
}

Finally, the transpose is obtained and it is printed on the screen. This is done with the following code snippet.

cout<<"The transpose of the matrix is:"<<endl;
for(i=0; i<c; ++i) {
   for(j=0; j<r; ++j)
   cout<<transpose[i][j]<<" ";
   cout<<endl;
}