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# Golang Program To Find The Transpose

In this article, we will write a go language program to find the transpose of a matrix. A matrix is a collection of numbers that are arranged in rows and columns, which is a two-dimensional array.

## Find The Transpose Of A Matrix

The following code illustrates an example to find the transpose of a matrix.

### Algorithm

**Step 1** − Import the fmt package.

**Step 2** − Call the main() function.

**Step 3** − Initialize a 2-d array called matrixA and matrix and store elements in it.

**Step 4** − Print the matrices on the screen.

**Step 5** − To find the transpose of these matrices iterate over the matrix using for loop and make a new matrix from the old one by changing each row of the matrix to the column.

**Step 6** − Once we have iterated over the matrix. Print the new matrix thus formed on the screen.

**Step 7** − Repeat the process for the second matrix and print it on the screen.

### Example

package main import ( "fmt" ) func main() { var i, j int var transposeMat [3][3]int matrixA := [3][3]int{ {0, 1, 2}, {4, 5, 6}, {8, 9, 10}, } fmt.Println("The first matrix is:") for i = 0; i < 3; i++ { for j = 0; j < 3; j++ { fmt.Print(matrixA[i][j], "\t") } fmt.Println() } fmt.Println() for i = 0; i < 3; i++ { for j = 0; j < 3; j++ { transposeMat[j][i] = matrixA[i][j] } } fmt.Println("The transpose of matrix is:") for i = 0; i < 3; i++ { for j = 0; j < 3; j++ { fmt.Print(transposeMat[i][j], "\t") } fmt.Println() } }

### Output

The first matrix is: 0 1 2 4 5 6 8 9 10 The transpose of matrix is: 0 4 8 1 5 9 2 6 10

## Find The Transpose Of A Matrix Using The Range Function

Let us now look at another method to find the transpose of a matrix in Go programming language.

### Algorithm

**Step 1** − Import the fmt package.

**Step 2** − Call the main() function.

**Step 3** − Initialize a 2-d array called matrixA and store elements in it. print this matrix on the screen using fmt.Println() function.

**Step 4** − To find the transpose of this matrix iterate over the matrix using the range function and make a new matrix from the old one by changing each row of the matrix to a column.

**Step 5** − Once we have iterated over the matrix. Print the new matrix thus formed on the screen.

### Example

package main import ( "fmt" ) func main() { var i, j int var transposeMat [3][3]int matrixA := [3][3]int{ {0, 1, 2}, {4, 5, 6}, {8, 9, 10}, } fmt.Println("The first matrix is:") for i = 0; i < 3; i++ { for j = 0; j < 3; j++ { fmt.Print(matrixA[i][j], "\t") } fmt.Println() } fmt.Println() for i, rows := range matrixA { for j := range rows { transposeMat[j][i] = matrixA[i][j] } } fmt.Println("The transpose of matrix, matrixA is:") for i, rows := range matrixA { for j := range rows { fmt.Print(transposeMat[i][j], "\t") } fmt.Println() } fmt.Println() }

### Output

The first matrix is: 0 1 2 4 5 6 8 9 10 The transpose of matrix, matrixA is: 0 4 8 1 5 9 2 6 10

## Conclusion

We have successfully compiled and executed a golang program to find the transpose of a matrix along with examples.

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