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# C++ program to find minimum difference between the sums of two subsets from first n natural numbers

Suppose we have a number n. Consider, first n natural numbers. We have to split them into two sets A and B such that each element belongs to exactly one set and the absolute difference between the sum of elements in A and sum of elements in B is minimum, and find that difference.

So, if the input is like n = 5, then the output will be 1, because if we make A = {1, 3, 4} and B = {2, 5}, then the sum values are 8 and 7, so difference is 1.

## Steps

To solve this, we will follow these steps −

return (n * (n + 1) / 2) mod 2

## Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h> using namespace std; int solve(int n) { return (n * (n + 1) / 2) % 2; } int main() { int n = 5; cout << solve(n) << endl; }

## Input

5

## Output

1

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