8085 program to find the sum of first n natural numbers
In this program we will see how to add first n natural numbers.
Problem Statement
Write 8085 Assembly language program to add first N natural numbers. The value of N is provided.
Discussion
We are getting the value of N from memory location 8000H. We are using the number N as count variable, in each step we are calculating (A + Count) value, and store them into A. After adding them, the count value is decreased,thus the total series is completed.
If the number is 23H(35D), then the sum will be (35*36)/2 = 630 (276H)
Input
Address
| Data
|
|---|
.
.
.
| .
.
.
|
8000
| 23
|
.
.
.
| .
.
.
|
Flow Diagram
Program
Address
| HEX Codes
| Labels
| Mnemonics
| Comments
|
|---|
F000
| 21, 00, 80
|
| LXI H,8000H
| Point to get the upper limit
|
F003
| 4E
|
| MOV C, M
| Load the upper limit to C
|
F004
| AF
|
| XRA A
| Clear the A register
|
F005
| 47
|
| MOV B, A
| Also clear B register
|
F006
| 81
| LOOP
| ADD C
| Add C with A
|
F007
| D2, 0B, F0
|
| JNC SKIP
| If CY = 0,Skip next step
|
F00A
| 04
|
| INR B
| Increase B ifCY = 1
|
F00B
| 0D
| SKIP
| DCR C
| Decrease C by1
|
F00C
| C2, 06, F0
|
| JNZ LOOP
| Until Z = 1,go to LOOP
|
F00F
| 21, 50, 80
|
| LXI H, 8050H
| Point to the destination address
|
F012
| 77
|
| MOV M, A
| Store the acc content
|
F013
| 23
|
| INX H
| Point to next location
|
F014
| 70
|
| MOV M, B
| Store the MSbyte
|
F015
| 76
|
| HLT
| Terminate the program
|
Output
Address
| Data
|
|---|
.
.
.
| .
.
.
|
8050
| 76
|
8051
| 02
|
.
.
.
| .
.
.
|
Published on 22-Jan-2019 10:06:01
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