Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find the average of first N natural numbers in C++
In this problem, we are given a number n. Our task is to find the average of first N natural numbers.
Average of numbers is defined as the sum of all numbers divided by the total number of numbers.
Average of N natural numbers is defined as the sum of first N natural numbers divided by N.
Let's take an example to understand the problem,
Input : N = 23 Output : 12
Explanation −
1 + 2 + 3 + ... + 22 + 23 = 276 276 / 23 = 12
Solution Approach
To find the average of the number we will use the formula for average which is,
Average = sum(N) / N
Average = (1 + 2 + 3 + ... + N) / N
We know that sum of N natural number is given by the formula,
$N^*(N+1)/2$
The average is,
Average = N*(N+1)/2*N = (N + 1)/2
Using this formula we can find the average of first N natural numbers.
Example
Program to illustrate the working of our solution
#include <iostream>
using namespace std;
float calcAverage(int n) {
return (float)( ((float)n + 1 )/2 );
}
int main() {
int N = 45;
cout<<"The average of first "<<N<<" natural numbers is "<<calcAverage(N);
return 0;
}Output
The average of first 45 natural numbers is 23
Updated on: 27-Jan-2022
485 Views
Advertisements