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C++ code to check phone number can be formed from numeric string
Suppose we have a string S with n digits. A number with exactly 11 digits is a telephone number if it starts with '8'. In one operation, we can remove one digit from S. We have to check whether we can make the string a valid phone number or not.
So, if the input is like S = "5818005553985", then the output will be True, because we can make the string "8005553985" with 11 characters and first digit is 8.
Steps
To solve this, we will follow these steps −
m := size of S insert '8' at the end of S if if location of 8 <= (m - 11), then: return true return false
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
bool solve(string S){
int m = S.size();
S.push_back('8');
if ((int(S.find('8')) <= (m - 11)))
return true;
return false;
}
int main(){
string S = "5818005553985";
cout << solve(S) << endl;
}Input
"5818005553985"
Output
1
Updated on: 11-Mar-2022
675 Views
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