Count pairs from two linked lists whose product is equal to a given value in C++

We are given with two linked lists and the task is to form the pairs using the integer elements of linked lists such that their product is equal to a given value which is let’s say, k. A linked list is a sequence of data structures, which are connected together via links.

Input

vector v_1 = {5, 7, 8, 10, 11},.
vector v_2 = {6, 4, 3, 2, 0} , int k = 20

Output

Count of pairs from two linked lists whose product is equal to a given value k are: 2

Explanation

The pairs which can be formed using the given linked lists are: (5, 6) = 30(not equals to k), (5, 4) = 20(equals to k), (5, 3) = 15(not equals to k), (5, 2) = 10(not equals to k), (5, 0) = 0(not equals to k), (7, 6) = 42(not equals to k), (7, 4) = 28(not equals to k), (7, 3) = 21(not equals to k), (7, 2) = 14(not equals to k), (7, 0) = 0(not equals to k), (8, 6) = 48(not equals to k), (8, 4) = 32(not equals to k), (8, 3) = 24(not equals to k), (8, 2) = 16(not equals to k), (8, 0) = 0(not equals to k), (10, 6) = 60(not equals to k), (10, 4) = 40(not equals to k), (10, 3) = 30(not equals to k), (10, 2) = 20(not equals to k), (10, 0) = 0(not equals to k), (11, 6) = 66(not equals to k), (11, 4) = 44(not equals to k), (11, 3) = 3(not equals to k), (11, 2) = 22(not equals to k), (11, 0) = 0(not equals to k). So, clearly there are 2 pairs which are equal to the given product.

Input

vector v_1 = {2, 3, 5, 6},.
vector v_2 = {6, 4, 3} , int k = 9

Output

Count of pairs from two linked lists whose sum is equal to a given value k are: 1

Explanation

The pairs which can be formed using the given linked lists are: (2, 6) = 12(not equals to k), (2, 4) = 8(not equals to k), (2, 3) = 6(not equals to k), (3, 6) = 18(not equals to k), (3, 4) = 12(not equals to k), (3, 3) = 9(equals to k), (5, 6) = 30(not equals to k), (5, 4) = 20(not equals to k), (5, 3) = 15(not equals to k), (6, 6) = 36(not equals to k), (6, 4) = 24(not equals to k), (6, 3) = 18(not equals to k),. So, clearly there is 1 pair which is equal to the given sum.

Approach used in the below program is as follows

Input the value of k and integer type values into two vectors such that we can pass the vectors to form a linked list
Create a function that will create a linked list using the vector passed as an argument to the function.
Traverse the loop till the size of a vector and create a pointer object of class
ListNode
- Traverse the loop while ptr-> next not equals to NULL and set ptr to ptr->next
- Inside the ptr->next set vector[i]
- Return start
Create a function that will return the count of pairs matching with the given product.
- Take a temporary variable count and set it to 0
- Create two pointer object i.e. *first_list for first linked list and *second_list for second linked list.
- Start loop from start pointer of first list till the list is not empty
- Inside the loop, start another loop from start pointer of second list till the list is not empty
- Inside the loop, check IF (first_list->data * second_list->data) == k then increment the count by 1
- Return the count
Print the result.

Example

Live Demo

#include<bits/stdc++.h>
using namespace std;
class ListNode{
public:
   int data;
   ListNode *next;
   ListNode(int data){
      this->data = data;
      next = NULL;
   }
};
ListNode *CreateList(vector v){
   ListNode *start = new ListNode(v[0]);
   for (int i = 1; i < v.size(); i++){
      ListNode *ptr = start;
      while (ptr->next != NULL){
         ptr = ptr->next;
      }
      ptr->next = new ListNode(v[i]);
   }
   return start;
}
int product_pair(ListNode *start_1, ListNode *start_2, int k){
   int count = 0;
   ListNode *first_list , *second_list;
   for (first_list = start_1; first_list != NULL; first_list = first_list->next){
      for (second_list = start_2; second_list != NULL; second_list = second_list->next){
         if ((first_list->data * second_list->data) == k){
            count++;
         }
      }
   }
   return count;
}
int main(){
   vector<int> v_1 = {5, 7, 8, 10, 11};
   ListNode* start_1 = CreateList(v_1);
   vector v_2 = {6, 4, 3, 2, 0};
   ListNode* start_2 = CreateList(v_2);
   int k = 30;
   cout<<"Count of pairs from two linked lists whose product is equal to a given value k are: "<<product_pair(start_1, start_2, k);
}

Output

If we run the above code it will generate the following output −

Count of pairs from two linked lists whose product is equal to a given value k are: 2

Sunidhi Bansal

Published on 02-Nov-2020 06:08:19

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