Convert given time into words in C++

C++Server Side ProgrammingProgramming

In this tutorial, we will be discussing a program to convert given time into words. For this we will be provided with a specific time in the digital format.Our task is to convert that particular time into words


#include <bits/stdc++.h>
using namespace std;
//printing time in words
void convert_time(int h, int m){
   char nums[][64] = {
      "zero", "one", "two", "three", "four",
      "five", "six", "seven", "eight",
      "nine","ten", "eleven", "twelve",
      "thirteen","fourteen", "fifteen",
      "sixteen", "seventeen","eighteen",
      "nineteen", "twenty", "twenty
      one","twenty two", "twenty three",
      "twenty four","twenty five", "twenty six",
      "twenty seven","twenty eight", "twenty nine",
   if (m == 0)
      printf("%s o' clock\n", nums[h]);
   else if (m == 1)
      printf("one minute past %s\n", nums[h]);
   else if (m == 59)
      printf("one minute to %s\n", nums[(h % 12) + 1]);
   else if (m == 15)
      printf("quarter past %s\n", nums[h]);
   else if (m == 30)
      printf("half past %s\n", nums[h]);
   else if (m == 45)
      printf("quarter to %s\n", nums[(h % 12) + 1]);
   else if (m <= 30)
      printf("%s minutes past %s\n", nums[m], nums[h]);
   else if (m > 30)
      printf("%s minutes to %s\n", nums[60 - m],nums[(h % 12) + 1]);
int main(){
   int h = 8;
   int m = 29;
   convert_time(h, m);
   return 0;


twenty nine minutes past eight
Published on 22-Jan-2020 06:52:11