# C program to convert digit to words

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Suppose we have a digit d, we shall have to convert it into words. So if d = 5, our output should be "Five". If we provide some d which is beyond the range of 0 and 9, it will return appropriate output.

So, if the input is like d = 6, then the output will be "Six".

To solve this, we will follow these steps −

• Define a function solve(), this will take d,
• if d < 0 and d > 9, then:
• return ("Beyond range of 0 - 9")
• otherwise when d is same as 0, then:
• return ("Zero")
• otherwise when d is same as 1, then:
• return ("One")
• otherwise when d is same as 2, then:
• return ("Two")
• otherwise when d is same as 3, then:
• return ("Three")
• otherwise when d is same as 4, then:
• return ("Four")
• otherwise when d is same as 5, then:
• return ("Five")
• otherwise when d is same as 6, then:
• return ("Six")
• otherwise when d is same as 7, then:
• return ("Seven")
• otherwise when d is same as 8, then:
• return ("Eight")
• otherwise when d is same as 9, then:
• return ("Nine")

## Example

Let us see the following implementation to get better understanding −

#include <stdio.h>
void solve(int d){
if(d < 0 && d > 9){
printf("Beyond range of 0 - 9");
}else if(d == 0){
printf("Zero");
}else if(d == 1){
printf("One");
}else if(d == 2){
printf("Two");
}else if(d == 3){
printf("Three");
}else if(d == 4){
printf("Four");
}else if(d == 5){
printf("Five");
}else if(d == 6){
printf("Six");
}else if(d == 7){
printf("Seven");
}else if(d == 8){
printf("Eight");
}else if(d == 9){
printf("Nine");
}
}
int main(){
int d = 6;

solve(d);
}


## Input

6

## Output

Six