# Compute the inverse hyperbolic tangent with scimath in Python

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To compute the inverse hyperbolic tangent with arctanh, use the numpy.emath.arctanh() method in Python. Returns the “principal value” of arctanh(x). For real x such that abs(x) < 1, this is a real number. If abs(x) > 1, or if x is complex, the result is complex. Finally, x = 1 returnsinf and x=-1 returns -inf.

The method returns the inverse hyperbolic tangent(s) of the x value(s). If x was a scalar so is out, otherwise an array is returned. The 1st parameter is the value(s) whose arctanh is (are) required.

## Steps

At first, import the required libraries −

import numpy as np

Create a numpy array using the array() method −

arr = np.array([0, 1j, 2j])


Display the array −

print("Array...\n", arr)

Get the type of the array −

print("\nOur Array type...\n", arr.dtype)


Get the dimensions of the Array −

print("\nOur Array Dimensions...\n",arr.ndim)

To compute the inverse hyperbolic tangent with arctanh, use the numpy.emath.arctanh() method in Python −

print("\nResult...\n",np.emath.arctanh(arr))


## Example

import numpy as np

# Create a numpy array using the array() method
arr = np.array([0, 1j, 2j])

# Display the array
print("Array...\n", arr)

# Get the type of the array
print("\nOur Array type...\n", arr.dtype)

# Get the dimensions of the Array
print("\nOur Array Dimensions...\n",arr.ndim)

# Get the number of elements in the Array
print("\nNumber of elements...\n", arr.size)

# To compute the inverse hyperbolic tangent with arctanh, use the numpy.emath.arctanh() method in Python
print("\nResult...\n",np.emath.arctanh(arr))

## Output

Array...
[0.+0.j 0.+1.j 0.+2.j]

Our Array type...
complex128

Our Array Dimensions...
1

Number of elements...
3

Result...
[0.+0.j 0.+0.78539816j 0.+1.10714872j]
Updated on 01-Mar-2022 08:02:05