Check if subarray with given product exists in an array in Python

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Suppose we have an array called nums and this contains positive and negative numbers. We have another value k. We have to check whether any subarray whose product is k is present in the array or not.

So, if the input is like nums = [-2,-1,1,3,5,8], k = 6, then the output will be True as the subarray is [-2,-1,3]

To solve this, we will follow these steps −

• minimum := nums[0], maximum := nums[0]
• prod_max := nums[0]
• for i in range 1 to size of nums - 1, do
  • if nums[i] < 0, then
    • swap maximum and minimum
  • maximum := maximum of nums[i] and (maximum * nums[i])
  • minimum := minimum of nums[i] and (minimum * nums[i])
  • if either minimum or maximum is same as k, then
    • return True
  • prod_max := maximum of prod_max and maximum
• return False

Let us see the following implementation to get better understanding −

Example Code

Live Demo

def solve(nums, k):
   minimum = nums[0]
   maximum = nums[0]
 
   prod_max = nums[0]
 
   for i in range( 1, len(nums)):
      if nums[i] < 0:
         maximum, minimum = minimum, maximum

      maximum = max(nums[i], maximum * nums[i])
      minimum = min(nums[i], minimum * nums[i])

      if minimum == k or maximum == k:
         return True
 
      prod_max = max(prod_max, maximum)
   return False

nums = [-2,-1,1,3,5,8]
k = 6
print(solve(nums, k))

Input

[-2,-1,1,3,5,8], 6

Output

True

Arnab Chakraborty

Updated on 15-Jan-2021 06:18:42

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