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Check if a pair with given product exists in a Matrix in C++
We have one matrix of order N x M. And a product K. The task is to check whether a pair with the given product is present in the matrix or not.
Suppose a matrix is like below −
| 1 | 2 | 3 | 4 |
| 5 | 6 | 7 | 8 |
| 9 | 10 | 11 | 12 |
| 13 | 14 | 15 | 16 |
Now if the K is 42, then there is a pair like (6, 7)
To solve this problem, we will use hashing. We will create hash table by taking all elements of the matrix. We will start traversing the matrix, while traversing, check whether the current element of the matrix is divisible by the given product, and when the product K is divided by current element, the dividend will also present in the hash table. So the required condition is like −
(k mod matrix[i, n]) is false, and hash table has k/matrix[i, j]
If present, then return true, otherwise insert current element into hash table.
If no pairs have found, return false.
Example
#include <iostream>
#include <unordered_set>
#define N 4
#define M 4
using namespace std;
bool isPairPresent(int matrix[N][M], int K) {
unordered_set<int> s;
for (int i = 0; i < N; i++) {
for (int j = 0; j < M; j++) {
if ((K % matrix[i][j] == 0) && (s.find(K / matrix[i][j]) != s.end())) {
return true;
} else {
s.insert(matrix[i][j]);
}
}
}
return false;
}
int main() {
int matrix[N][M] = {{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}};
int k = 42;
if (isPairPresent(matrix, k) == false)
cout << "NO PAIR EXIST";
else
cout << "Pair is present";
}Output
Pair is present
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