Suppose we have a number which is either in octal or in decimal form. If this is in octal form check whether it is palindrome or not. If the number in decimal, then convert it to octal then check whether it is palindrome or not.
So, if the input is like num = 178, then the output will be True as the number is not in octal form (8 is not valid symbol in octal but valid in decimal), then convert it to octal which is 262 and this is palindrome.
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
def is_all_under_8(num): while num: if (num % 10) >= 8: return False else: num = int(num / 10) return True def solve(num): base = 8 if(is_all_under_8(num) == False) else 10 oct_list =  while num != 0: oct_list.append(num % base) num = int(num / base) j = len(oct_list)-1 k = 0 while k <= j: if oct_list[j] != oct_list[k]: return False j-=1 k+=1 return True num = 178 print(solve(num))