# Check if a number is Primorial Prime or not in Python

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Suppose we have a number n, we have to check whether n is a primorial prime or not. A number is said to be a primorial prime when it is a prime number of the form pN# + 1 or pN# – 1 , where pN# indicates the primorial of pN such that the product of first N prime numbers.

So, if the input is like 29, then the output will be True as 29 is Primorial prime of the form pN - 1 if N=3, Primorial is 2*3*5 = 30 and 30-1 = 29.

To solve this, we will follow these steps −

• MAX := 100000
• prime := A list of size MAX and fill with True
• arr := a new list
• Define a function SieveOfEratosthenes() . This will take
• for pri in range 2 to int(square root of (MAX)) + 1, do
• if prime[pri] is same as True, then
• for i in range pri * 2 to MAX, update in each step by pri, do
• prime[i] := False
• for pri in range 2 to MAX, do
• if prime[pri] is non-zero, then
• insert pri at the end of arr
• From the main method, do the following −
• if prime[n] is zero, then
• return False
• product := 1, i := 0
• while product < n, do
• product := product * arr[i]
• if product + 1 is same as n or product - 1 is same as n, then
• return True
• i := i + 1
• return False

## Example

Let us see the following implementation to get better understanding −

Live Demo

from math import sqrt
MAX = 100000
prime = [True] * MAX
arr = []
def SieveOfEratosthenes() :
for pri in range(2, int(sqrt(MAX)) + 1) :
if prime[pri] == True :
for i in range(pri * 2 , MAX, pri) :
prime[i] = False
for pri in range(2, MAX) :
if prime[pri] :
arr.append(pri)
def check_primorial_prime(n) :
if not prime[n] :
return False
product, i = 1, 0
while product < n :
product *= arr[i]
if product + 1 == n or product - 1 == n :
return True
i += 1
return False
SieveOfEratosthenes()
n = 29
print(check_primorial_prime(n))

## Input

29

## Output

True
Updated on 27-Aug-2020 13:41:55