Can we overload methods of an interface in Java?


Polymorphism is the ability of an object to perform different actions (or, exhibit different behaviors) based on the context.

Overloading is one of the mechanisms to achieve polymorphism where a class contains two methods with the same name and different parameters.

Whenever you call this method the method body will be bound with the method call based on the parameters.

Example

In the following Java program, the Calculator class has two methods with name addition the only difference is that one contains 3 parameters and the other contains 2 parameters.

Here, we can call the addition method by passing two integers or three integers. Based on the number of integer values we pass respective method will be executed.

 Live Demo

public class Calculator {
   public int addition(int a , int b){
      int result = a+b;
      return result;
   }
   public int addition(int a , int b, int c){
      int result = a+b+c;
      return result;
   }
   public static void main(String args[]){
      Calculator cal = new Calculator();
      System.out.println(cal.addition(12, 13, 15));
   }
}

Output

40

Overloading methods of an interface

Yes, you can have overloaded methods (methods with the same name different parameters) in an interface. You can implement this interface and achieve method overloading through its methods.

Example

 Live Demo

import java.util.Scanner;
interface MyInterface{
   public void display();
   public void display(String name, int age);
}
public class OverloadingInterfaces implements MyInterface{
   String name;
   int age;
   public void display() {
      System.out.println("This is the implementation of the display method");
   }
   public void display(String name, int age) {
      System.out.println("Name: "+name);
      System.out.println("Age: "+age);
   }
   public static void main(String args[]) {
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter your name: ");
      String name = sc.next();
      System.out.println("Enter your age: ");
      int age = sc.nextInt();
      OverloadingInterfaces obj = new OverloadingInterfaces();
      obj.display();
      obj.display(name, age);
   }
}

Output

Enter your name:
Krishna
Enter your age:
25
This is the implementation of the display method
Name: Krishna
Age: 25
raja
Published on 10-Sep-2019 14:34:47
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