Can the abstract methods of an interface throw an exception in java?

Yes, the abstract methods of an interface can throw an exception.

Example

In the following example the interface (MyInterface) contains an abstract method with name display, which throws an IOException.

import java.io.IOException;
abstract interface MyInterface {
   public abstract void display()throws IOException ;
}

Rules to be followed

You need to follow the rules given below while implementing such method −

• If the abstract method in the interface throws certain exception. The implemented method can throw the same exception as shown below −

Example 1

 Live Demo

import java.io.IOException;
abstract interface MyInterface {
   public abstract void display()throws IOException ;
}
public class InterfaceExample implements MyInterface{
   public void display()throws IOException {
      System.out.println("This is the subclass implementation of the display method");
   }
   public static void main (String args[]){
      try {
         new InterfaceExample().display();
      }
      catch (Exception e) {
         e.printStackTrace();
      }
   }
}

Output

This is the subclass implementation of the display method

• If the abstract method in the interface throws certain exception. The implemented method can choose not to throw any exception as shown below −

Example 2

 Live Demo

import java.io.IOException;
abstract interface MyInterface {
   public abstract void display()throws IOException ;
}
public class InterfaceExample implements MyInterface{
   public void display() {
      System.out.println("This is the subclass implementation of the display method");
   }
   public static void main (String args[]){
      try {
         new InterfaceExample().display();
      }
      catch (Exception e) {
         e.printStackTrace();
      }
   }
}

Output

This is the subclass implementation of the display method

• If the abstract method in the interface throws certain exception. The implemented method can throw its subtype −

Example 3

 Live Demo

import java.io.IOException;
abstract interface MyInterface {
   public abstract void display()throws Exception ;
}
public class InterfaceExample implements MyInterface{
   public void display()throws IOException {
      System.out.println("This is the subclass implementation of the display method");
   }
   public static void main (String args[]){
      try {
         new InterfaceExample().display();
      }
      catch (Exception e) {
         e.printStackTrace();
      }
   }
}

Output

This is the subclass implementation of the display method

• If the abstract method in the interface throws certain exception. The implemented method should not throw its super type

Example 4

 Live Demo

import java.io.IOException;
abstract interface MyInterface {
   public abstract void display()throws IOException ;
}
public class InterfaceExample implements MyInterface{
   public void display()throws Exception {
      System.out.println("This is the subclass implementation of the display method");
   }
   public static void main (String args[]){
      try {
         new InterfaceExample().display();
      }
      catch (Exception e) {
         e.printStackTrace();
      }
   }
}

Compile time error

Output

InterfaceExample.java:8: error: display() in InterfaceExample cannot implement display() in MyInterface
   public void display()throws Exception {
               ^
   overridden method does not throw Exception
1 error

Maruthi Krishna

Published on 04-Jul-2019 13:44:59

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