What happens if a class does not implement all the abstract methods of an interface in java?

Java 8Object Oriented ProgrammingProgramming

Interface in Java is similar to class but, it contains only abstract methods and fields which are final and static.

In a separate class you need to implement this interface and provide body for all its abstract methods.

Once you implement an interface using a class, you must provide body (implement) to all of its abstract methods or, should declare the class as abstract. If you don’t a compile time error will be generated for each unimplemented method saying “InterfaceExample is not abstract and does not override abstract method method_name in interface_name”.

In the following java program, we have an interface with name MyInterface with 3 abstract methods and, a class implementing this interface, with name InterfaceExample.

In the class we are providing body for only one abstract method (display()).

Example

import java.util.Scanner;
interface MyInterface{
   public void display();
   public void setName(String name);
   public void setAge(int age);
}
public class InterfaceExample implements MyInterface{
   int age;
   String name;
   public void display() {
      if(18 < this.age && this.age < 26) {
         System.out.println("Hello "+this.name+" welcome");
      } else {
         System.out.println("Under age");
      }
   }  
   public static void main(String args[]) {
   }
}

Compile time error

On compiling the above program generates the following error

Output

InterfaceExample.java:7: error: InterfaceExample is not abstract and does not
override abstract method setAge(int) in MyInterface
public class InterfaceExample implements MyInterface{
^
1 error

To make this program work, you need to implement all the abstract methods in the class or, declare the class abstract, as shown below −

Example

import java.util.Scanner;
interface MyInterface{
   public void display();
   public void setName(String name);
   public void setAge(int age);
}
public class InterfaceExample implements MyInterface{
   int age;
   String name;
   public void display() {
      if(18 < this.age && this.age < 26) {
         System.out.println("Hello "+this.name+" welcome");
      } else {
         System.out.println("Under age");
      }
   }
   public void setName(String name){
      this.name = name;
   }
   public void setAge(int age){
      this.age = age;
   }
   public static void main(String args[]) {
      Scanner sc = new Scanner(System.in);
      InterfaceExample obj = new InterfaceExample();
      System.out.println("Enter name:");
      obj.setName(sc.next());
      System.out.println("Enter age:");
      obj.setAge(sc.nextInt());
      obj.display();
   }
}

Output

Enter name:
Krishna
Enter age:
25
Hello Krishna welcome
raja
Published on 04-Jul-2019 13:32:47
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