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Caesar Cipher in Python
Suppose we have a lowercase alphabet string s, and an offset number say k. We have to replace every letter in s with a letter k positions further along the alphabet. We have to keep in mind that when the letter overflows past a or z, it gets wrapped around the other side.
So, if the input is like "hello", k = 3, then the output will be "khoor"
To solve this, we will follow these steps −
Define a function shift(). This will take c
i := ASCII of (c) - ASCII of ('a')
i := i + k
i := i mod 26
return character from ASCII (ASCII of ('a') + i)
From the main method, do the following −
ret := for each character c in s, make a list of elements by calling shift(c)
return ret
Let us see the following implementation to get better understanding −
Example
class Solution:
def solve(self, s, k):
def shift(c):
i = ord(c) - ord('a')
i += k
i %= 26
return chr(ord('a') + i)
return "".join(map(shift, s))
ob = Solution()
print(ob.solve("hello", 3))Input
"hello", 3
Output
khoor
Updated on: 02-Sep-2020
981 Views
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